How to send multipart/form-data to server using Ajax, PHP and jQuery?

Question

I have a form where I need to send name of the user along with his profile image. So I have created the form below using HTML & Bootstrap -

 <form action="" method="post" id="demoForm" enctype="multipart/form-data">
    <div class="form-group">
        <label for="">Upload file</label>
        <input type="file" name="file" id="file" class="form-control">
    </div>
    <div class="form-group">
        <label for="">Your Name</label>
        <input type="text" name="name" id="name" class="form-control">
    </div>
    <div class="form-group">
        <input type="submit" name="save" id="save" value="Save" class="form-control btn btn-success">
    </div>
 </form>
<div id="result"></div>

Now I need to send this data to my server using PHP. So I have written the following Ajax code using jQuery -

$(document).ready(function(){
    $('#demoForm').submit(function(e){
        e.preventDefault();
        var formData = new FormData(this);
        $.ajax({
            url: "ajax.php",
            type: "POST",
            data: formData,
            contentType : false,
            processData: false,
            success: function(data){
                $('#result').html(data);
            }
        });
    });
});

Now I have written the following PHP code in ajax.php file -

if(isset($_POST['save'])){

    $name = $_POST['name'];
    $file = $_FILES['file']['name'];

    if(!empty($file) && !empty($name)){
        $fileName = $_FILES['file']['name'];
        $tmp = $_FILES['file']['tmp_name'];
        $upload = move_uploaded_file($tmp,'uploads/'.$fileName);
       if($upload){
            echo "<h2>".$name.", your file has been uploaded successfully!</h2>";
       }else{
           echo "<h2>Something went wrong!</h2>";
       }
    }else{echo "File cannot be empty.";}
}else{echo "There is a problem";}

Now, the issue is that I don't get any response from the php file. In other words, the ajax.php file is not receving the data sent through Ajax from the index.php file. Can anyone please help me by pointing out what mistakes I have done? Also share if any solution is there with you. Thanks.

score 1 · Answer 1 · answered Oct 17 '19 at 18:41

1

You are submitting the form from Ajax so the $_POST['save'] variable will not be set . And therefore the code inside the if block will not run . Remove this line if(isset($_POST['save'])){ from your PHP code and rewrite it like this

$name = $_POST['name'];
$file = $_FILES['file']['name'];

if(!empty($file) && !empty($name)){
    $fileName = $_FILES['file']['name'];
    $tmp = $_FILES['file']['tmp_name'];
    $upload = move_uploaded_file($tmp,'uploads/'.$fileName);
   if($upload){
        echo "<h2>".$name.", your file has been uploaded successfully!</h2>";
   }else{
       echo "<h2>Something went wrong!</h2>";
   }
}

answered Oct 17 '19 at 18:41

sh1hab

661
5
16

1

Wow! I can't imagine how to thank you. You have given me the solution that I spent almost 24 hours to debug. Thank yo very much. It worked. – Anjan Talukdar Oct 17 '19 at 18:52
@AnjanTalukdar I am glad to hear that . You can encourage us by upvoting and accepting the answer – sh1hab Oct 17 '19 at 18:54

score 0 · Answer 2 · answered Oct 17 '19 at 18:34

if(isset($_POST['save'])){ is the problem.

The submit button will only be a successful control if it is used to submit the form.

Your JavaScript is cancelling the submission of the form and making a request using a FormData object instead.

Test for the existence of some other piece of data, make save a hidden input, or remove the check entirely.

You have three if statements in your PHP. Only one of them has an else to output an error. Adding else with messages to the other two would make it easier for you to debug your code.

Thank you for your time. It'd be better if you could tell me the solution. — Anjan Talukdar, Oct 17 '19 at 18:39

How to send multipart/form-data to server using Ajax, PHP and jQuery?

2 Answers2