Does there exist any RTL Delphi function to determine the position of the last occurrence of a char in a string?
5 Answers
try the LastDelimiter
function which is part of the SysUtils unit.
-
2System.SysUtils.TStringHelper.LastIndexOf could also be handy when you want a string instead of a character. – Gabriel Apr 07 '17 at 08:59
RRUZ answered the actual question (he gave you a RTL function).
Still, I cannot quite resist giving a simple code snippet that does what you want:
function LastCharPos(const S: string; const Chr: char): integer;
var
i: Integer;
begin
result := 0;
for i := length(S) downto 1 do
if S[i] = Chr then
Exit(i);
end;
Since this does exactly what you want and offer no other features, it is far more compact (especially when we use the Exit(Result)
syntax of Delphi 2009 and later) and probably slightly faster. In Delphi 2007, however, you have to do
function LastCharPos(const S: string; const Chr: char): integer;
var
i: Integer;
begin
result := 0;
for i := length(S) downto 1 do
if S[i] = Chr then
begin
result := i;
break; // or Exit; if you prefer that
end;
end;

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Use StrRScan
or AnsiStrRScan
, both in the SysUtils unit. The latter, despite its name, works on Unicode characters in the Delphi versions where string
is UnicodeString
. (If you still need the "real" Ansi version, use the AnsiStrings unit.)
These functions search for exactly one character, whereas LastDelimiter
searches for any of several characters from the given list of possibilities — think of StrRScan
as LastDelimiter
optimized for a one-character Delimiters
argument.

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The best cross-platform solution is TStringHelper.LastIndexOf, it exists since Delphi XE4.
Note, that this function is 0-based.
And here's my contribution for finding the position of the nth occurrence of a substring within a string.
function GetPositionOfNthOccurence(sSubStr, sStr: string; iNth: integer): integer;
var
sTempStr: string;
iIteration: integer;
iTempPos: integer;
iTempResult: integer;
begin
result := 0;
// validate input parameters
if ((iNth < 1) or (sSubStr = '') or (sStr = '')) then exit;
// evaluate
iIteration := 0;
iTempResult := 0;
sTempStr := sStr;
while (iIteration < iNth) do
begin
iTempPos := Pos(sSubStr, sTempStr);
if (iTempPos = 0) then exit;
iTempResult := iTempResult + iTempPos;
sTempStr := Copy(sStr, iTempResult + 1, Length(sStr) - iTempResult);
inc(iIteration);
end;
result := iTempResult;
end;

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very good, because with this code also is possible determine quantity of occurences of a substring in a string. This solved a trouble to me now! thank you by your contribution. – Oct 05 '17 at 18:32