Is there a Function to ignore chars like 'á' 'é' 'ó' 'í' and 'ú'?

Question

Im doing a caesar cipher and decipher, and i need to ignore this letters from the String: "á é ó í ú", cause we need to cipher text in spanish too, is there any function to ignore this letters or a way to change them in the cipher and still work in the decipher?

private char cipher(char ch, int key)
        {
            if (!char.IsLetter(ch))
            {
                return ch;
            }
            char d = char.IsUpper(ch) ? 'A' : 'a';
            return (char)((((ch + key) - d) % 26) + d);
        }

something i expect is, if i enter a String like : "wéts" with a key an2, i get an output "uéiy" and when i decipher the "uéiy" i get "wéts" again

This looks like modulo math on a 26 character (Latin?) alphabet - which is clearly not going to work when you accept more than the 26 characters. Teach your system about the other characters. — Sam Axe, Oct 18 '19 at 18:40

score 1 · Accepted Answer · answered Oct 18 '19 at 18:55

Sure, here you go, here's 65536 character alphabet caesar cipher implementation:

private char cipher(char ch, int key)
{
  return ch + key;
}
private char decipher(char ch, int key)
{
  return ch - key;
}

or here's one that just ignore non-latin letters:

private char cipher(char ch, int key)
{
  if (char < 'A' || char > 'z' || (char > 'Z' && char < 'a'))
  {
    return ch;
  }
  char d = char.IsUpper(ch) ? 'A' : 'a';
  return (char)((((ch + key) - d) % 26) + d);
}

oh thanks, that works for this project, thank you – Esteban Oct 18 '19 at 19:14 — Esteban, Oct 18 '19 at 19:14

Is there a Function to ignore chars like 'á' 'é' 'ó' 'í' and 'ú'?

1 Answers1