word in list in tokenized sentence

Question

I have a list of words / appliances

appliances = ['tv', 'radio', 'oven', 'speaker']

I also have a sentence, which I have tokenized.

sent = ['We have a radio in the Kitchen']
sent1 = word_tokenize[sent]

I want to say that if appliances are in sent1 then print yes else print no. I did the below but keep getting no as the print.

if any(appliances) in sent1:
    print ('yes')
else:
    print ('no')

Is there a better way of doing this?

@JerryM. `any` returns a bool – smac89 Oct 21 '19 at 15:10 — smac89, Oct 21 '19 at 15:10

Florian Bernard · Accepted Answer · 2019-10-21T15:22:33.660

3

Try something like this.

appliances = ['tv', 'radio', 'oven', 'speaker']
sent = ['We have a radio in the Kitchen']
sent1 = list(sent[0].split())

if any([app in sent1 for app in appliances]):
    print ('yes')
else:
    print ('no')

Edit based on @tobias_k comments

Use lazy evaluation.

if any(app in sent1 for app in appliances):
    print ('yes')
else:
    print ('no')

Edit : based on @ben121 comment

If you want to see with appliance are in your sentence you could do like this.

[app for app in appliances if app in sent1]

edited Oct 21 '19 at 15:22

answered Oct 21 '19 at 15:13

Florian Bernard

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2

Better use `any(app in sent1 for app in appliances)` to make use of lazy-evaluation. – tobias_k Oct 21 '19 at 15:15
Thanks. Works well. What would I do to print what app appeared in the list. In this instance instead of printing yes it prints radio. – ben121 Oct 21 '19 at 15:19
1

@ben121 code updated – Florian Bernard Oct 21 '19 at 15:23

word in list in tokenized sentence

1 Answers1

Edit based on @tobias_k comments

Edit : based on @ben121 comment