BREAK using Regex in JAVA

Question

I'm new to using Regex I want to get macapp value in url just get number 12 to String how do that ?

String url = "stackoverflow.com/questions/ask:macapp=12";

Pattern pattern = ;// ?

Matcher matcher =;// ?


if(matcher.find()) 
{
    //result = only 12
}

THX for your TIME

It's not quite clear what your question is. Do you want to extract a number that appears at the end of a string? Or a number that appears after the word `macapp=`? What does break have to do with it? — Eritrean, Oct 21 '19 at 21:45

score 1 · Accepted Answer · answered Oct 21 '19 at 22:13

1

Pattern p = Pattern.compile("^.*:macapp=(\\d+)$");
Matcher m = p.matcher(s);
if (m.find()) {
  int n = Integer.valueOf(m.group(1));
  ...
}

answered Oct 21 '19 at 22:13

Jeffrey Blattman

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thx man please make this pattern https://stackoverflow.com/questions/58509600/finding-the-after-matching-string-in-java – abbas mehrabian Oct 22 '19 at 17:38

BREAK using Regex in JAVA

1 Answers1