How do I extract code from redirected url? (OAuth 2.0, Flask)

Question

So the authorization request url is correct and it successfully redirects to redirect_url which is /loginAuthorized. I can plainly see that a code is added as in

http://127.0.0.1:5000/loginAuthorized/?code=SOME_CODE`

but can't grab it on the code. When I print path, it just prints loginAuthorized/ wihtout code. I can ask users to manually copy paste code from url, but it will not be convenient so want to avoid asking that.

import re
import requests
from flask import Flask, render_template

app = Flask(__name__)

@app.route('/')
def main():

    # encoded url with information needed to request an authorization
    url = "https://kauth.kakao.com/oauth/authorize?client_id=MY_CLIENT_ID&redirect_uri=http%3A%2F%2F127.0.0.1%3A5000%2F%2FloginAuthorized/&response_type=code"
    return render_template('index.html', request_url=url) 

# If you authorize the service, it redirected to this url
# Catch any url that has /loginAuthorized as its base
@app.route("/loginAuthorized", defaults={"path": ""})
@app.route("/<path:path>")
def loginAuthorized(path):
    print('a')
    print(path)  # "loginAuthorized/" is printed, there is no code
    print('b')

if __name__ == "__main__":
    app.run()

Talha Junaid · Accepted Answer · 2019-10-22T06:05:45.140

1

You can use request flask module to get query params from URL

Import request using

from flask import request

Then to get code query param from URL use. request.args.get('code')

edited Oct 22 '19 at 06:05

answered Oct 22 '19 at 02:44

Talha Junaid

2,351
20
29

That was much easier than I thought. Thank you. (p.s. This module is needed `from flask import request`) – PuffedRiceCrackers Oct 22 '19 at 02:56
Updated answer. – Talha Junaid Oct 22 '19 at 06:06

How do I extract code from redirected url? (OAuth 2.0, Flask)

1 Answers1