Wrong input thrown up python

Question

I'm writing a basic text adventure game for practice, but when I start this up, no matter what I press, it prints Start normally, then goes to the pot of gold part, adds 10 to G and then ends. For some reason it seems to ignore that there are other possibilities than the first in the if, elif, else statements. Any ideas why this might be and how I could fix it?

start=input("Start")
if start=='yes' or 'Yes':
    G=0
    R=0
    K=0
    u=input("L/R?")
    if u=='l' or 'L':
        L1=input("You see a pot of gold. It has a note attached reading 'please do not take'")
        if L1=='take' or 'Take':
            G=G+10
        else:
            K=K+1

    elif u=='r' or 'R':
        R1=input("You see a burning pyre with a golden goblet placed in front of it. There are strange carvings on the wall")
        if R1=='worship' or 'Worship':
            R=R+10
        elif c1=='take goblet' or 'Take goblet' or 'take' or 'Take':
            R=R-5
            G=G+15
        else:
            K=K+1
else:
  sys.exit
print(G)
print(R)
print(K)

The condition `u == 'l' or 'L'` is always true. You could use `u == 'l' or u == 'L'` or `u in 'lL'` or `u.lower() == 'l'`. — mkrieger1, Oct 23 '19 at 13:27

score 0 · Answer 1 · answered Oct 23 '19 at 13:27

0

Use

if u=='l' or u=='L':

instead of

if u=='l' or 'L':

answered Oct 23 '19 at 13:27

anshulk

458
5
13

That fixed it, thanks. And I fixed the errors I'd thrown up for myself with R1 being mixed with c1 – Isosceles Oct 23 '19 at 13:31

Wrong input thrown up python

1 Answers1