I couldn't figure this out after spending 2 days of Google search and trials.
Question: Is there any way to use a regular expression that includes \u
or \x
?
What I want to do: I am reading a long text in string, and I need to check if that text contains the following pattern:
\20\999\u[0-f]{4}
So for example, if the text includes \20\30\u001a, it needs to be true and I actually need to retrieve this value. (By the way, the real regular expression is way longer than this, but I shortened it for convenience.)
The code I have that is not working:
private string re = @"\20\999\u[0-9a-f]{4}";
private Match CheckIfMatches(string textToBeChecked)
{
Regex regex = new Regex(this.re, RegexOptions.IgnoreCase);
return regex.Match(textToBeChecked)
}
private void DoSomeOperation(string textToBeChecked)
{
string s = "";
try
{
Match matchResult = CheckIfMatches(textToBeChecked);
if(result.Success)
{
s = result.Value;
//Do more operations
}
else
{
//Do more operations
}
}
catch(Exception ex)
{
//Do error handling
}
}
When I test-run this program with some text, it returns an error and it goes to the exception with Insufficient Hexadecimal Digits. I know this is happening because the regular expression contains \u. But I actually need to include this in the regular expression.
I tried removing @
, and also adding one extra \
to see if it makes any difference, but it didn't.
How can I use a regular expression in C# with \u
or \x
?
Edit:
Below is a part of the whole string stored in textToBeChecked
as the entire string is too long, and also it is confidential.
Test sample test sample test sample \03\02\0\u0010\ test sample test sample
Something like above is stored in this variable. And the actual code I am using is
private string re = @"\\03\\02\\0\\u[0-9a-f]{4}";
result.Success
in my code in the original question returns false
to this.