Javascript check all values of object and it's nested object

Question

Hi i'm currently stuck with this problem of checking an object that has another nested object if all value in it is null or 0

My object is as follow:

{
   "city":0,
   "road":{
      "max":null,
      "min":null
   },
   "size":{
      "max":null,
      "min":null
   },
   "type":null,
   "ward":0,
   "floor":null,
   "price":{
      "max":null,
      "min":null
   },
   "street":0,
   "toilet":null,
   "balcony":null,
   "bedroom":null,
   "district":0,
   "frontend":{
      "max":null,
      "min":null
   },
   "direction":null,
   "living_room":null
}

i need to check every single values in it is 0 or null , return true if all values is either 0 or null, false if any of the values different than null or 0

i can't use :

Object.values(object).every(i => (i === null || i === ''))

It return False since the nested object still consider as a different value than 0 and null

I don't want to write super long if condition check every single value of it at a time

Is there anyway to iterate over the object and it's nested object to check ?

Nina Scholz · Accepted Answer · 2019-10-25T07:49:42.790

3

You could take an iterative and recursive approach.

function check(object) {
    return Object.values(object).every(v => v && typeof v === 'object'
        ? check(v)
        : v === 0 || v === null
    );
}

var data0 = { city: 0, road: { max: null, min: null }, size: { max: null, min: null }, type: "sell", ward: 0, floor: null, price: { max: null, min: null }, street: 0, toilet: null, balcony: null, bedroom: null, district: 0, frontend: { max: null, min: null }, direction: null, living_room: null },
    data1 = { city: 0, road: { max: null, min: null }, size: { max: null, min: null }, type: null, ward: 0, floor: null, price: { max: null, min: null }, street: 0, toilet: null, balcony: null, bedroom: null, district: 0, frontend: { max: null, min: null }, direction: null, living_room: null };

console.log(check(data0)); // false because of type: "sell"
console.log(check(data1)); // true

edited Oct 25 '19 at 07:49

answered Oct 25 '19 at 07:37

Nina Scholz

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shouldn't it return true if every v equal null or 0 ? or am i mistaken ? – Linh Nguyen Oct 25 '19 at 07:44
right, it does. but you have `type: "sell"`, which is not `null` or zero. – Nina Scholz Oct 25 '19 at 07:47
oh yeah my bad forgot to edit that, type supposed to be null – Linh Nguyen Oct 25 '19 at 07:48

score 2 · Answer 2 · answered Oct 25 '19 at 07:34

One (inelegant) option is to use JSON.stringify with a callback, and whenever a value other than 0 or null is found, set a flag:

const obj = {
   "city":0,
   "road":{
      "max":null,
      "min":null
   },
   "size":{
      "max":null,
      "min":null
   },
   "type":"sell",
   "ward":0,
   "floor":null,
   "price":{
      "max":null,
      "min":null
   },
   "street":0,
   "toilet":null,
   "balcony":null,
   "bedroom":null,
   "district":0,
   "frontend":{
      "max":null,
      "min":null
   },
   "direction":null,
   "living_room":null
};

let allZeroNull = true;
JSON.stringify(obj, (key, val) => {
  if (typeof val !== 'object' && val !== 0) {
    allZeroNull = false;
  }
  return val;
});
console.log(allZeroNull);

Or, to do it more manually, with short-circuiting:

const obj = {
   "city":0,
   "road":{
      "max":null,
      "min":null
   },
   "size":{
      "max":null,
      "min":null
   },
   "type":"sell",
   "ward":0,
   "floor":null,
   "price":{
      "max":null,
      "min":null
   },
   "street":0,
   "toilet":null,
   "balcony":null,
   "bedroom":null,
   "district":0,
   "frontend":{
      "max":null,
      "min":null
   },
   "direction":null,
   "living_room":null
};

const isAllZeroNull = (item) => {
  if (typeof item === 'object' && item !== null) {
    for (const val of Object.values(item)) {
      if (!isAllZeroNull(val)) {
        return false;
      }
    }
  } else if (item !== 0 && item !== null) {
    return false;
  }
  return true;
};
console.log(isAllZeroNull(obj));

LMAO! I'm here just trying to really search if a property with a specific name or value exists and never thought to just dump it to a JSON string and search that. — Shawn Mclean, Aug 25 '22 at 22:29

score 1 · Answer 3 · answered Oct 25 '19 at 07:37

You can can create a function (fn) that uses Object.values() to get an array of values, iterate with Array.every() and if the value is an object use fn on it:

const fn = data =>
  Object.values(data)
  .every(v => {
    if(v === null || v === 0) return true;
    
    return typeof v === 'object' ? fn(v) : false;
  })

const data = {"city":0,"road":{"max":null,"min":null},"size":{"max":null,"min":null},"type":"sell","ward":0,"floor":null,"price":{"max":null,"min":null},"street":0,"toilet":null,"balcony":null,"bedroom":null,"district":0,"frontend":{"max":null,"min":null},"direction":null,"living_room":null}

const result = fn(data)

console.log(result)

Javascript check all values of object and it's nested object

3 Answers3