How to remove scalar property from an object?

Question

I'm trying to create new object from an array of values. I don't know to create new object. So I added following lines.

$object = (object) '';
$object->vehicleId = $vehicleId;

But it automatically adds a new property scalar in the object. How to remove it?

Just do `$object = new stdClass;` or if you have an array of values, just `$object = (object)$array;` — AbraCadaver, Oct 25 '19 at 13:09
maybe he was already in a different namespace than `\ ` @AbraCadaver — N69S, Oct 25 '19 at 13:16
@N69S: Well then learning PHP and namespaces would be a start ;-) — AbraCadaver, Oct 25 '19 at 13:17
@AbraCadaver you could also be more precise and say do `new \stdClass()` — N69S, Oct 25 '19 at 13:18
@N69S that's not necessary unless the current namespace you're working in happens to have a class named StdClass, which seems exceeding unlikely. Same reason you don't have to prefix `substr()` or `preg_match()` eg — miken32, Oct 25 '19 at 14:01
Possible duplicate of [How to define an empty object in PHP](https://stackoverflow.com/questions/1434368/how-to-define-an-empty-object-in-php) — miken32, Oct 25 '19 at 14:02
@AbraCadaver stdClass instantiation wont work like functions. You should try it. — N69S, Oct 25 '19 at 15:09
@N69S: I have no idea what you are talking about https://3v4l.org/9t0e9 — AbraCadaver, Oct 25 '19 at 15:14
@N69S That is what you get if you do not define full name for your classes. https://3v4l.org/QjJoB — Dharman, Oct 25 '19 at 15:19

Dharman · Answer 1 · 2019-10-25T15:41:31.517

As per the PHP Manual:

If an object is converted to an object, it is not modified. If a value of any other type is converted to an object, a new instance of the stdClass built-in class is created. If the value was NULL, the new instance will be empty. An array converts to an object with properties named by keys and corresponding values. Note that in this case before PHP 7.2.0 numeric keys have been inaccessible unless iterated.

When you cast a string to an object the value of that string will be saved as an attribute. The default name is given which is scalar. Even an empty string is still considered to hold a value.

In PHP you have multiple ways of creating an empty object.

An example taken from https://www.php.net/manual/en/language.types.object.php#118679

<?php
$obj1 = new \stdClass; // Instantiate stdClass object
$obj2 = new class{}; // Instantiate anonymous class
$obj3 = (object)[]; // Cast empty array to object

var_dump($obj1); // object(stdClass)#1 (0) {}
var_dump($obj2); // object(class@anonymous)#2 (0) {}
var_dump($obj3); // object(stdClass)#3 (0) {}

Another way would be to cast a null value to an object as N69S shown:

$object = (object)null; // Same as (object)[]

And of course you can convert an associative array to an object:

$object = (object)['a' => 123];

// object(stdClass)#1 (1) {
//   ["a"]=>
//  int(123)
// }

score 0 · Answer 2 · edited Oct 25 '19 at 15:34

0

You can instantiate an object stdClass with new:

$object = new stdClass();
$object->vehicleId = $vehicleId;

edited Oct 25 '19 at 15:34

Dharman

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answered Oct 25 '19 at 13:14

Jean Marcos

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score 0 · Answer 3 · answered Oct 25 '19 at 13:15

0

you can just do it the conventional way

$object = new \stdClass();

or with null conversion

$object = (object)null;

and if you already have an array, you can convert it to object

$object = (object)$array;

answered Oct 25 '19 at 13:15

N69S

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How to remove scalar property from an object?

3 Answers3