array python || time.strftime

Question

i want a print current index of array using:

import os
import datetime
import time

a = time.strftime("%d", time.localtime())
list1 = ["123", 123, 123, 132, 123, 123, 123, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
print(list1[a])
input('Press ENTER to exit')

But console is close What happen?

What does "*console is close (error)*" mean? Please provide all output (and error messages) that you are getting. — walnut, Oct 25 '19 at 16:18
@uneven_mark Console not have errors.. Console closing. I edited code. — huh_again, Oct 25 '19 at 16:20
Python is not responsible for closing your console. What OS are you using and how are you running the script? Try opening a command line and running the script from there, so that you can see all error messages printed, after Python exited. — walnut, Oct 25 '19 at 16:22
I am not too familiar with Windows. Try [this question](https://stackoverflow.com/questions/4621255/how-do-i-run-a-python-program-in-the-command-prompt-in-windows-7), although it may be out-of-date for Python 3.x (I don't know). — walnut, Oct 25 '19 at 16:33

score 0 · Answer 1 · answered Oct 25 '19 at 16:24

0

I dont think you can pass a string to a list index

print(list1[a]) # Lists take integers as indices

answered Oct 25 '19 at 16:24

Mohammed Yahya

9
2

As i said you're expilicitly passing a string to an array list[] – Mohammed Yahya Oct 25 '19 at 16:32
The interpreter is seeing [a] as an integer, so it gives you a Type error! – Mohammed Yahya Oct 25 '19 at 16:35

score 0 · Accepted Answer · answered Oct 25 '19 at 16:30

I don't know what does it means that the console is closing without an error.

when running you code I get the following, using python 2.7:

>>> print(list1[a])
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: list indices must be integers, not str

This is caused because the return of time.strftime("%d", time.localtime()) is a string variable.

The change in your code needs to be:

print(list1[int(a)])

which will transform that string into an integer.

do notice that there is a lot of issue you need to take care of:

make sure that the number string you assigning to a is valid
make sure you you don't enter an index that does not exist

score 0 · Answer 3 · answered Oct 25 '19 at 16:38

0

Try this instead, i hope it gives you the output you needed!

a = int(time.strftime("%d", time.localtime()))
list1 = ["123", 123, 123, 132, 123, 123, 123, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1]
print(list1[a])

answered Oct 25 '19 at 16:38

Mohammed Yahya

9
2

array python || time.strftime

3 Answers3