Let's say I have this list:
List= [1,1,1,0,0,1,1,1,1,1]
How do I display the highest number of repeating 1s in a row? I want to return 5.
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1What code have you already tried? – ofthegoats Oct 26 '19 at 21:54
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Is the list always going to contain only 1s and 0s? – ofthegoats Oct 26 '19 at 21:55
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Actually, I'm still a beginner and I have no idea what to try. And no it won't necessarily contain zeros and ones, any 2 repeating values – user12279644 Oct 26 '19 at 21:57
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so you want the highest number of consecutive elements in list? Am I right? – Mouse on the Keys Oct 26 '19 at 22:03
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If you have no idea you should first do some research and try something and post some code before asking for a solution to your problem. – whbogado Oct 26 '19 at 22:05
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Yes, you're right – user12279644 Oct 26 '19 at 22:05
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I did the research and came up with no result – user12279644 Oct 26 '19 at 22:06
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Mouse on the Keys.. Thank you so much – user12279644 Oct 26 '19 at 22:20
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@user112279644 no problems just next time be more specific with defining your question please, read help section how to ask question, and help us to help you... – Mouse on the Keys Oct 26 '19 at 22:26
2 Answers
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I don`t really understand the question, but if you want the highest number of consecutive elements in list, maybe something like this
from itertools import groupby
list = [1,1,1,0,0,1,1,1,1,1]
count_cons_val = [sum(1 for _ in group) for _, group in groupby(list)]
print(max(count_cons_val))
Output:
5
Mouse on the Keys
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Find my comments how this answer helps you out inline after the # tag.
save = None
count = 0
best = 0
for i in list:
if i == save:
count += 1 # if it's the same as last add 1 to count
best = count
else: #if it is different reset with the new element
count = 0
save = i
print(best)
