I have a list of srings:
lista = ['Word', 'Apple', 'Banana']
How can I convert this into regex:
reg = "\b(word1|word2|word3)\b"
My target is to speed-up my function (for a dataframe):
df['A'] = df['A'].replace(reg, r'\XXX', regex=True)
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PV8
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`regex = r'\b(' + "|".join(list) + r')\b'`. but its not a good idea to call your list as `list` as you will overwrite the python built in of list – Chris Doyle Oct 29 '19 at 12:34
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thx, with the error: multiple repeat at postion , I have to do `regex = re.escape(..) `or? – PV8 Oct 29 '19 at 12:37
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Sorry i dont get what you mean. When i test with `print(re.findall(regex, "This is an Apple tree and not a Banana tree"))` i get the output `['Apple', 'Banana']` so the regex works – Chris Doyle Oct 29 '19 at 12:42
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yeah, but this is a sample dataset, If I have different data in it... – PV8 Oct 29 '19 at 12:44
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I can only work off the sample you provided – Chris Doyle Oct 29 '19 at 12:45