Python 3 : How to create a list of lists based on the range function

Question

I'm trying to create a list from a range, but when I stick it in another list I get a class and not the list of lists that I'm expecting - [[0,1,2]]

Code:

    initial_list = range(3)
    list_of_lists = [initial_list]
    for i in list_of_lists:
    print(i, type(i))

This outputs range(0,3), <class 'range'> However, I want [[0,1,2]] Does anyone know how to force range to expand?

simply replace `range(3)` with `list(range(3))` – Dan Oct 29 '19 at 15:21 — Dan, Oct 29 '19 at 15:21

score 2 · Accepted Answer · answered Oct 29 '19 at 15:24

2

This answer explains that you're pretty close! If you were in Python 2.x, this approach would have worked, since in 2.x, range() returns a list. In 3.x, however, range() returns an iterator.

Expand it with list(range(3)) to get the desired result.

answered Oct 29 '19 at 15:24

Nick Reed

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score 1 · Answer 2 · edited Oct 29 '19 at 16:43

1

You could append it to anotehr list. Heres what i've done do to this:

initial_list = []
for i in range(3):
 initial_list.append(i)
list_of_lists = [initial_list]

Then in IDLE it Showed:

list_of_lists
[0, 1, 2]]

edited Oct 29 '19 at 16:43

Antoine Delia

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answered Oct 29 '19 at 15:30

Nifri

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Python 3 : How to create a list of lists based on the range function

2 Answers2