How to divide 2 integer numbers and get the output stored in float variable using ksh shell scripting?

Question

I have below values stored in the respective variables:

s=$(nice grep -i "sf WOW" *`date --date='1 hour ago' +%y%m%d%H`* | grep -i "TRAF:5" | wc -l)
f=$(nice grep -i "sf WOW" *`date --date='1 hour ago' +%y%m%d%H`* | grep -i "TRAF:7" | wc -l)
a=`expr $s + $f`

I need to store the division output in a float variable with an accuracy of 5 digits.

s=$(nice grep -i "sf WOW" *`date --date='1 hour ago' +%y%m%d%H`* | grep -i "TRAF:5" | wc -l) f=$(nice grep -i "sf WOW" *`date --date='1 hour ago' +%y%m%d%H`* | grep -i "TRAF:7" | wc -l) a=`expr $s + $f` — Sachin Aravind, Oct 30 '19 at 08:52
The code is getting modified with some formatting syntax of this website. — Sachin Aravind, Oct 30 '19 at 08:52
`ksh` is not `bash`. They are different. `ksh` doesn't accept heredocs introduced with `<<<` because that is a *"bash-ism"*. — Mark Setchell, Oct 30 '19 at 09:04
I can store value using this command. x=$(bc -l <<< '10/13') But I want to use variables in that command instead of values. — Sachin Aravind, Oct 30 '19 at 09:07
To check your shell, try `echo $0` as the next line in your script. Then `ps -p "$$"` — Mark Setchell, Oct 30 '19 at 09:10
If you want variables expanded, you must use double quotes, not single quotes. — Mark Setchell, Oct 30 '19 at 09:11
I am using ksh. echo $SHELL /bin/ksh So could you please give a command which supports in ksh? — Sachin Aravind, Oct 30 '19 at 09:12
a=$(echo "x/y" | bc) Runtime error (func=(main), adr=5): Divide by zero — Sachin Aravind, Oct 30 '19 at 09:20
It didn't work. a=$(echo "scale=5; $s/$f" | bc) (standard_in) 1: syntax error — Sachin Aravind, Oct 30 '19 at 09:24
Then try `s=1.11111; f=2.22222` and run the previous `echo` again. — Mark Setchell, Oct 30 '19 at 09:30
echo "scale=5; $x + $y" scale=5; 52 + 58 But in my case, both x and y are integer variables. I need to do x/y and store z as a float value. — Sachin Aravind, Oct 30 '19 at 09:42
I don't why is this behaving like below. No clue. echo "scale=5; $x + $y" scale=5; 52 + 58 hi=`echo "scale=2;2/3" |bc` echo $hi .66 hi=`echo "scale=2;x/y" |bc` Runtime error (func=(main), adr=11): Divide by zero echo $x 52 echo $y 58 — Sachin Aravind, Oct 30 '19 at 10:00
Hey Mark, Thank you so much! It worked for me. z=$(echo "scale=2; $x * 100 / $y" | bc) echo $z 89.65 Thanks a ton!! Really appreciate it! — Sachin Aravind, Oct 30 '19 at 10:11
How do I mark your comment as the solution? If you can write it as a separate reply I would definitely mark that as the solution to this question. Thank you! — Sachin Aravind, Oct 30 '19 at 10:12
I can't do that as the question is closed for being a duplicate. But don't worry, be happy! Good luck with your project. — Mark Setchell, Oct 30 '19 at 10:15
@SachinAravind : I guess you have ksh93, because earlier ksh version don't have floating point numbers. But then, you should be able to do simply `a=s+f`, provided that you declared the variables expicitly as _float_. — user1934428, Oct 30 '19 at 10:39

xoid · Answer 1 · 2019-10-30T08:49:45.880

1

echo "scale=5; 355/113" | bc
3.14159

edited Oct 30 '19 at 08:49

answered Oct 30 '19 at 08:42

xoid

1,114
1
10
24

Hi bro, it didn't work. – Sachin Aravind Oct 30 '19 at 08:49
echo "scale=5; x/a" | bc -l Runtime error (func=(main), adr=11): Divide by zero echo $a 110 echo $x 52 – Sachin Aravind Oct 30 '19 at 08:49
@SachinAravind `$a` is the bash variable. If you replace xoids example `355/113` with `x/a`, you need to assign the `bc` variables `a` and `x` first: `echo "scale=5; x=$x; a=$a; x/a" | bc -l` - or simply: `echo "scale=5; $x/$a" | bc -l` – Ted Lyngmo Oct 30 '19 at 12:09

How to divide 2 integer numbers and get the output stored in float variable using ksh shell scripting?

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