Printing a block of elements in a list

Question

Is there a good way to print n elements of a list, for example 10, after that the next 10 numbers?

    liste = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]
    for i in range(0,len(liste),10):
        for j in range(10):
        print(liste[j])

This just prints the numbers from 1-10 and begins at 1 again.

I want something like this:

1,2,3,4,5,6,7,8,9,10
11,12,13,14,15,16,17,18,19,20

bassically cut the list into parts of n elements the same size.

Rithin Chalumuri · Accepted Answer · 2019-10-30T11:06:27.853

3

Use python list slicing:

your_list = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20]

for i in range(0, len(your_list), 10):
    chunk = your_list[i:i+10]
    print(','.join(list(map(str,chunk))))

Outputs:

1,2,3,4,5,6,7,8,9,10
11,12,13,14,15,16,17,18,19,20

Related links:

How do you split a list into evenly sized chunks?

edited Oct 30 '19 at 11:06

answered Oct 30 '19 at 10:29

Rithin Chalumuri

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Does exactly what i wanted. Thank you. – Emanuel Oct 30 '19 at 10:34
@Emanuel, glad that it's solved. And if my answer is helpful, could you please help accept it? Thanks :) – Rithin Chalumuri Oct 30 '19 at 10:35
@RithinChalumuri `join()` is a string method. This fails when you run it with the given list with `TypeError: sequence item 0: expected str instance, int found`. – David Buck Oct 30 '19 at 10:43
1

It will work if you change the print to `print(','.join(list(map(str,your_list[i:i+10]))))` to convert the ints to str before the join. – David Buck Oct 30 '19 at 10:50
@DavidBuck, thanks for pointing out I typed this on the go without testing, so I will update the answer now. – Rithin Chalumuri Oct 30 '19 at 11:04

score 0 · Answer 2 · answered Oct 30 '19 at 10:28

0

The value of j runs from 0 to 9 on every iteration.

Try print(liste[i*10+j]).

answered Oct 30 '19 at 10:28

goodvibration

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Printing a block of elements in a list

2 Answers2