Python: Execute code when the next minute starts

Question

So I am exploring automation in my program, and I need it to run code every time the next minute starts, an example:

Let's say it is 8:12:32, I would want it to run at 8:13:00 instead of 8:13:32

Because of this, sleep doesn't work for my purposes.

I was searching around Stack Overflow for an answer before I opened a question and I found something like this:

def minute_passed(oldepoch):
    return time.time() - oldepoch >= 60

However, it has to be manually called every time I want to check. I need it to continuously test.

Sorry, Python is kind of a new experience for me.

Currently using Python 3.6 and Windows

@AndrewChon You can use [sched](https://docs.python.org/3/library/sched.html) or check this [answer](https://stackoverflow.com/a/49053648/3091398). — CodeIt, Nov 02 '19 at 03:37

score 1 · Accepted Answer · answered Nov 02 '19 at 03:52

1

From a comment by Codelt

You can use sched or check this answer

answered Nov 02 '19 at 03:52

Andrew Chon

score 1 · Answer 2 · answered Nov 02 '19 at 05:50

1

If you know time in seconds, then you can try

sleep(60 - seconds)

answered Nov 02 '19 at 05:50

Tabin1000

2 Answers2