1

This is my string: 

data = abdskjfdskjfjkdseiruiskdfdsdfjsdjkfdsdfsdjk

I want to split my data into 10s

So, I want my output to look like: 

abdskjfdsk
jfjkdseiru

and so on for the rest of the string.

I tried: 

chunks, chunk_size = len(data), len(data)//10
[ data[i:i+chunk_size] for i in range(0, chunks, chunk_size) ]

but it didn't change anything and my output was 

data = abdskjfdskjfjkdseiruiskdfdsdfjsdjkfdsdfsdjk

EDIT: This solved the issue: 

import re
re.findall('.{10}', data)

Thank you !!

Mina
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2 Answers2

1

Use re.findall

>>> import re
>>> re.findall('.{10}', data)
['abdskjfdsk', 'jfjkdseiru', 'iskdfdsdfj', 'sdjkfdsdfs']

. matches any character (except for line terminators)

{10} Quantifier — Matches exactly 10 times

Vishnudev Krishnadas
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1

when you have a string, you can subset by each of the elements of the string using brackets []. This is, if you want the first three elements fo your list you can use:

data[0:3]

next, we'll harness a list comprehension technique to do this process multiple times:

[data[character:character+10] for character in range(0, len(data),10)]
Ana Preciado
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