How to turn a integer into a list

Question

Suppose I have integer

n = 504

I want it to be a list like this

ls = [5, 0, 4]

How can I approach? Here is my solution:

n = 504
tmpList = list(str(n))
ls = [int(i) for i in tmpList]

Any better way to do it?(probably a shorter way)

Perhaps `[int(i) for i in str(504)]`? – Chris Nov 04 '19 at 05:28 — Chris, Nov 04 '19 at 05:28

score 1 · Accepted Answer · edited Nov 04 '19 at 05:32

1

Try this:

[int(i) for i in str(504)]

Output:

[5,0,4]

edited Nov 04 '19 at 05:32

Sayandip Dutta

answered Nov 04 '19 at 05:30

2

This solution was already proposed by Chris in comment – kuro Nov 04 '19 at 05:31
Ok I did not see – Yogesh Nikam Patil Nov 04 '19 at 05:32

Tim Biegeleisen · Answer 2 · 2019-11-04T05:34:54.140

1

Perhaps a bit overkill, but you could use re.findall here:

n = 504
parts = re.findall(r'\d', str(n))
print(parts)

['5', '0', '4']

Use map if you want a list of actual integers:

parts = results = map(int, parts)
print(parts)

[5, 0, 4]

edited Nov 04 '19 at 05:34

answered Nov 04 '19 at 05:31

Tim Biegeleisen

Note that, I want the items inside the list to be integer not string. – Saykat Nov 04 '19 at 05:32
1

Check the updated answer. – Tim Biegeleisen Nov 04 '19 at 05:35
Yeah got it. Thanks. – Saykat Nov 04 '19 at 05:36

score 0 · Answer 3 · answered Nov 04 '19 at 05:34

0

With a while loop it could be:

num = 504
result = []

while num > 10:
  mod = num % 10
  num = num // 10
  result = [mod] + result

result = [num] + result


print(result)

answered Nov 04 '19 at 05:34

developer_hatch

score 0 · Answer 4 · answered Nov 04 '19 at 05:36

0

You may try this:

n = 504
lst = list(map(int,str(n)))
print(lst)

Output:

[5,0,4]

answered Nov 04 '19 at 05:36

Sayandip Dutta

4 Answers4