how to replace(($24.39)) as 24.39 using preg_replace in php?

Question

Why don't you just use str_replace? The pattern is `(($` and `))`, I see no reason to use regular expressions for that. — Michael J.V., May 03 '11 at 11:41
I agree with Michael. In this case using str_replace would be good. — Nobita, May 03 '11 at 11:42

score 5 · Answer 1 · edited May 23 '17 at 10:34

5

Instead of preg_replace or str_replace you could also use filter_var:

echo filter_var(
    '(($24.39))', 
    FILTER_SANITIZE_NUMBER_FLOAT, 
    FILTER_FLAG_ALLOW_FRACTION
); // 24.39

Related but not applicable as a solution for your given string: PHP: unformat money

edited May 23 '17 at 10:34

Community

answered May 03 '11 at 11:51

Gordon

score 2 · Answer 2 · answered May 03 '11 at 11:44

2

you could try:

$str = "(($24.39))";
$str = preg_replace('/[^\.\d]/',"",$str);
echo $str;

answered May 03 '11 at 11:44

Ian Wood

would concur with Michael and Niobita - IF that is the consistent pattern. str_replace is much more efficient... – Ian Wood May 03 '11 at 11:46

score 2 · Accepted Answer · answered May 03 '11 at 11:51

If you had a large string with multiple occurrences and wanted to replace those in that pattern only...

$str = preg_replace('/\(\((\$\d+\.\d+)\)\)/', '$1', $str);

If you wanted to make the decimal optional, you could change the \.\d+ to (?:\.\d+)?.

score 1 · Answer 4 · answered May 03 '11 at 11:53

1

Regex are expensive. Use:

$str = '(($24.39))';
$str = str_replace('(($', '', $str);
$str = str_replace('))', '', $str);

answered May 03 '11 at 11:53

Shoe

4 Answers4