Why 5<4<2 is returning true?

Question

I am practicing Javascript. I came across one scenario where I am comparing 3 numbers as below:

console.log(5<4<2);

It returns true. Now that I don't understand why. By operator precendence it must evaluate left to right which means false<2. Is something strange done by js in this case?

The comparison: `(5 < 4) < 2 => false < 2 => 0 < 2 == true`. — Teemu, Nov 04 '19 at 10:57

Mamun · Accepted Answer · 2019-11-04T11:05:13.283

2

This is because of the Operator precedence.

Less than (<) operator is evaluated from left-to-right.

First 5<4 is evaluated to false then false is converted to 0 in the next evaluation. Finally 0<2 is evaluated to true

console.log(5<4);// false
console.log(0<2);// true

edited Nov 04 '19 at 11:05

answered Nov 04 '19 at 10:58

Mamun

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why is it converted to 0? – Vinay Prajapati Nov 04 '19 at 12:36
@VinayPrajapati, being the right operand is a number the left operand is coerced (convert) to the number type and the number type of `false` is `0`:) – Mamun Nov 04 '19 at 12:45

Why 5<4<2 is returning true?

1 Answers1