How to slice a certain portion of an image in python?

Question

I have an input image that has a mouth photo in a dark background: input image

I want only the mouth portion as output: output image

Considering using an [image processing library](https://opensource.com/article/19/3/python-image-manipulation-tools) like PIL/Pillow. — mario_sunny, Nov 04 '19 at 12:58
check out this https://stackoverflow.com/questions/13538748/crop-black-edges-with-opencv — Pritish kumar, Nov 04 '19 at 13:13

score 0 · Answer 1 · answered Nov 04 '19 at 13:03

0

Use https://scikit-image.org/ library. You can crop it as easy as below.

from skimage import io
image = io.imread(filename)
cropped = image[x1:x2,y1:y2]

answered Nov 04 '19 at 13:03

Jasag

1
1

he is probably talking about this https://stackoverflow.com/questions/13538748/crop-black-edges-with-opencv – Pritish kumar Nov 04 '19 at 13:13

score 0 · Accepted Answer · answered Nov 04 '19 at 13:12

Try this Crop black edges with OpenCV

import numpy as np
import cv2

img = cv2.imread('./data/q18.png')

gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
#play with parameters that all I changed in answer
_,thresh = cv2.threshold(gray,20,255,cv2.THRESH_BINARY)

# and here are 3 value returned not 2 
_,contours,_ = cv2.findContours(thresh,cv2.RETR_EXTERNAL,cv2.CHAIN_APPROX_SIMPLE)
cnt = contours[0]
x,y,w,h = cv2.boundingRect(cnt)


crop = img[y:y+h,x:x+w]
cv2.imwrite('./data/q18_1.png',crop)

Output:

score 0 · Answer 3 · answered Nov 04 '19 at 14:12

Like this with PIL/Pillow:

#!/usr/bin/env python3

from PIL  import Image

# Load image and convert to greyscale
im = Image.open('mouth.png').convert('L') 

# Threshold at 40
thr = im.point(lambda p: p > 40 and 255)

# Find bounding box
bbox = thr.getbbox()

# Debug
print(bbox)

# Crop and save
result = im.crop(bbox)
result.save('result.png')

Sample Output

(70, 155, 182, 223)

How to slice a certain portion of an image in python?

3 Answers3