Incremental number with specific format

Question

I need to make an id with a specific format where 2 first digit are year, and the rest are just incremental number with 000 as spacer between year and incremental number where the qty of 0 will decrease along with increasingly incremental number such as 190001,190002,.....,190180,...,191400. All i can think of using

$id = '';
if(srtrlen($number) == 1){
   $id = date('y',time()).'000'.$number;
}
elseif(strlen($number)==2){
   $id = date('y',time()).'00'.$number;
}
.
.
.
else{
   $id = date('y',time()).$number;
}

score 0 · Accepted Answer · answered Nov 05 '19 at 07:27

0

You can use str_pad.

$id = '';
if(srtrlen($number) == 1){
    $id = date('y',time()).str_pad($number, 3, '0', STR_PAD_LEFT);
}
elseif(strlen($number)==2){
   $id = date('y',time()).str_pad($number, 2, '0', STR_PAD_LEFT);
}
.
.
.
else{
   $id = date('y',time()).$number;
}

answered Nov 05 '19 at 07:27

Poldo

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27

You could always use `str_pad($number, 4-strlen($number), '0', STR_PAD_LEFT)` to save the `if...` – Nigel Ren Nov 05 '19 at 07:30

Incremental number with specific format

1 Answers1