My date is save in db as 08/07/1990. I want to display it in web as 08 july 1990
When I use this format date('d-F-Y',strtotime($date));
It display as 07 Aug 1990 instead of 08 july 1990.
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Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed. Check more here: php.net/manual/en/function.strtotime.php
$dateInput = '08/07/1990';
$date = str_replace('/', '-', $dateInput);
echo date('d-F-Y', strtotime($date));
//08-July-1990
Upvote if found your answer. *but one thing is clear that if you saved year as 1990 then it can't possible to make it 2019.
Prahsant Sharma
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what....... this is 100% false – treyBake Nov 09 '19 at 11:43
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i tried it and working very well here. try again it is working code – Prahsant Sharma Nov 09 '19 at 11:51
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I'm not on about the code, I'm on about your whole first paragraph – treyBake Nov 09 '19 at 11:51
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means code solved your problem? if then why downvote. – Prahsant Sharma Nov 09 '19 at 12:04
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because the explanation is incorrect. You can create a date from a format - there is no date assumption. Date requires a date to be in YYYY-MM-DD format – treyBake Nov 09 '19 at 14:15
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its not working – php developer Nov 11 '19 at 05:42