I would like to either open a file when my program is run, or alternatively, print a clickable link to the file. After reading some similar-looking questions on SO, I tried as follows:
f = open('C:/Users/User/Documents/example.xlsx')
print(f.name)
however, this just prints the file directory as text, so I can't just click on it to open the file.
Is it possible to do what I am asking?
