Finding max value of an array and displaying it in another function

Question

I need to find the max value (b) of the array then take that value convert it then put everything into another function and display it like so: "Lake Baikal:1640.43 meters."

function lakeDepth() {
  let lakeData = {
    "Caspian Sea": 560,
    "Tarn Hows": 53,
    "Crater Lake": 324,
    "Lake Tanganyika": 803,
    "Lake Vostok": 546,
    "Lake Baikal": 897,
  };
  result = Object
    .keys(lakeData)
    .sort(function(a, b) {
      return lakeData[b] - lakeData[a];
    })
    .map(Number);

  console.log(result);

}
lakeDepth();

function fathomsToMeter() {
  let deepestInMeter = result * 1.8288;
  return deepestInMeter;

}

function displayData() {
  console.log(result + deepestInMeter + "meter");


}

how do i get just the "b" part of the array do the calculation in the function and put it together at the end? thanks in advance for any help.

You don't have an ***array*** here. You have an ***object***. Additionally, you have a syntax error with your object - - you need to remove the final comma after the last key/value pair in the object. — Scott Marcus, Nov 10 '19 at 16:54

Zubeyir · Answer 1 · 2019-11-10T17:01:43.987

You can easily find deepest lake as below, regarding to your code;

    let lakeData = {
            "Caspian Sea": 560,
            "Tarn Hows": 53,
            "Crater Lake": 324,
            "Lake Tanganyika": 803,
            "Lake Vostok": 546,
            "Lake Baikal": 897,
        };
    
    let _deepest = 0
    let _key = ""

    Object.keys(lakeData).forEach(function(key) {
      if (lakeData[key] > _deepest)
      {
        _deepest = lakeData[key]
        _key = key
      }
    });
    
    console.log(lakeData[_key], _key)

Loop through all keys in object, follow their values and compare in every iteration, and find the biggest one.

Answers should describe what the original problem was and how your code solves the problem. Not just include working code. — Scott Marcus, Nov 10 '19 at 16:57

Frazer · Accepted Answer · 2019-11-11T11:00:22.877

0

Your code gives an array of lake names sorted by depth, so all that was needed was to select the first from that array using [0], then select the actual depth using lakeData[nameOfLake] which looks into the lakeData object and returns the value of the key nameOfLake.

Let me know if you have any questions.

const lakeData = {
  "Caspian Sea": 560,
  "Tarn Hows": 53,
  "Crater Lake": 324,
  "Lake Tanganyika": 803,
  "Lake Vostok": 546,
  "Lake Baikal": 897
};

const lake = Object.keys(lakeData).sort((a, b) => lakeData[b] - lakeData[a])[0];

console.log(`${lake}: ${lakeData[lake] * 1.8288} metres`);

Following your comment of 11/11:
An example of a template literal with a new line:

console.log(`The Deepest lake is: ${lake}
This lake is ${lakeData[lake] * 1.8288}m deep.`)

edited Nov 11 '19 at 11:00

answered Nov 10 '19 at 16:56

Frazer

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Answers should describe what the original problem was and how your code solves the problem. Not just include working code. – Scott Marcus Nov 10 '19 at 16:57
@ScottMarcus Fair point, hopefully my edit is useful to steakman. – Frazer Nov 10 '19 at 17:03
*Hopefully this answer also shows how code can be made simpler.* is not an explanation of what your code does or how it works. – Scott Marcus Nov 10 '19 at 17:06
Thank you Frazer, this is working and is short, but how would i console.log it in another function? as i cant seem to connect the lakedata if i consolel.og it in another function, also how can i edit the jquery part? i havent used it before i need to add the .toFixed(2), thank you in advance – steakman Nov 11 '19 at 09:58
so i got this console.log, i just need to add the .toFixed(2) and need to present it in another function how would i go about doiung this? console.log("The Deepest lake is: " + `${lake}` + "\n" + "This lake is " + `${lakeData[lake] * 1.8288}` + "m deep.") – steakman Nov 11 '19 at 10:16
@steakman the ${x} bits aren't jquery but template literals. You use a backtick ` instead of sing or double quotes; within those backticks the pattern ${abc} will match a variable, in this case the variable abc. It's an alternative to building a string via +=. As an added bonus you don't need a \n for a new line, just put your output on another line within the literal. I'll add to my answer for an example. – Frazer Nov 11 '19 at 10:54
@Frazer ok perfect thank you – steakman Nov 11 '19 at 12:37
@steakman great, glad to have helped. If you find an answer helpful you can upvote it and/or mark it as the accepted answer. This encourages people to contribute. – Frazer Nov 11 '19 at 14:35
1

@Frazer i upvoted it but it only shows after 15 reputation, so it says atleast. – steakman Nov 12 '19 at 18:25
Thank you, and well done for getting your reputation points. – Frazer Nov 22 '19 at 13:06

Finding max value of an array and displaying it in another function

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