I would like to take a feature and spread it's values as columns with 1/0 if true/false e.g.
mtcars %>%
pivot_wider(names_from = cyl,
values_from = 1)
This appears to have done something, cyl has now been spread into columns except the values are things like 21, 21.4 or NA.
> mtcars %>%
+ pivot_wider(names_from = cyl,
+ values_from = 1)
# A tibble: 32 x 12
disp hp drat wt qsec vs am gear carb `6` `4` `8`
<dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl> <dbl>
1 160 110 3.9 2.62 16.5 0 1 4 4 21 NA NA
2 160 110 3.9 2.88 17.0 0 1 4 4 21 NA NA
3 108 93 3.85 2.32 18.6 1 1 4 1 NA 22.8 NA
4 258 110 3.08 3.22 19.4 1 0 3 1 21.4 NA NA
5 360 175 3.15 3.44 17.0 0 0 3 2 NA NA 18.7
6 225 105 2.76 3.46 20.2 1 0 3 1 18.1 NA NA
7 360 245 3.21 3.57 15.8 0 0 3 4 NA NA 14.3
8 147. 62 3.69 3.19 20 1 0 4 2 NA 24.4 NA
9 141. 95 3.92 3.15 22.9 1 0 4 2 NA 22.8 NA
10 168. 123 3.92 3.44 18.3 1 0 4 4 19.2 NA NA
I tried using values_fill
like so:
> mtcars %>%
+ pivot_wider(names_from = cyl,
+ values_from = 1,
+ values_fill = list(1 = 0))
Error: unexpected '=' in:
" values_from = 1,
values_fill = list(1 ="
How can I spread cyl across columns with binary 1 or 0 values depending on whether or not the cyl is 4, 6 or 8?
Is pivot_wider() what I want?