PHP problem if(strtoupper(preg_replace('/\s+/' , $_POST["msg"])=="TEXT")

Question

Do you know where is problem with this code:

I see all the time: Parse error: syntax error, unexpected ';' 2

PHP problem with this code:

if(strtoupper(preg_replace('/\s+/' ,$_POST["msg"])=="TEXT"){
$mysqli = new mysqli("localhost", "serwer33830_db", "ICh*%m@72112L@&", "serwer33830_db");

I don't know where what is wrong in line:

if(strtoupper(preg_replace('/\s+/' ,$_POST["msg"])=="TEXT"){

See https://www.php.net/manual/en/function.preg-replace.php , you're missing a required parameter — aynber, Nov 13 '19 at 16:18

score 0 · Answer 1 · answered Nov 13 '19 at 16:19

0

if(strtoupper(preg_replace('/\s+/' ,$_POST["msg"])=="TEXT")){

missing ) before {

answered Nov 13 '19 at 16:19

Labradorcode

381
3
15

Labradorcode thanks! – Rafał Nov 13 '19 at 17:17

PHP problem if(strtoupper(preg_replace('/\s+/' , $_POST["msg"])=="TEXT")

1 Answers1