shell linux don't execute commande

Question

I have this command and it works fine on shell. I want to run it with php but it does not work what i missed :

edited :

$arg="arg1"; $arg2= "arg2";

echo shell_exec("sshpass -p ".escapeshellarg($arg)." ssh -t root@00.00.00.00 'asterisk -rx ".escapeshellarg($arg2)."'");

after this change no error on output but still commande not executed

edited : the original commande is like this :

sshpass -p 'arg1' ssh -t root@00.00.00.00 'asterisk -rx "arg2"'

and i want to around the probleme with external parameters but it does not work

The problem that you're using single quote inside double qoutes to use functions. `echo shell_exec("sshpass -p ".escapeshellarg($arg)." ssh -t root@00.00.00.00 'asterisk -rx ".escapeshellarg($arg2)."'");` this will work. — Mohammed Alhanafi, Nov 14 '19 at 01:44

score 0 · Answer 1 · answered Nov 14 '19 at 09:10

0

If the php is running on safe mode, it won't allow to execute shell_exec as it's described in the php manual:. https://www.php.net/manual/en/ini.sect.safe-mode.php

You can disabled the safe mode for a certain folder as it's described in the Stack Overflow question:

answered Nov 14 '19 at 09:10

Code Rage

Can you edit the original post to replace the single quotes to double quotes as advised on the comment above and describe the output or which error do you receive. – Code Rage Nov 14 '19 at 10:20

score 0 · Accepted Answer · answered Nov 14 '19 at 22:44

Finally I found a good solution for who still search :

I installed php-ssh2 with this link (i use debian 8, php7)

and in my case i use codeigniter i follow the link to implement this class

now i can execute any commande on shell without probleme

and the probleme is solved :)

Hope its help someone :)

2 Answers2