How do I enumerate a list without parenthesis?

Question

I have this python code, yet it adds parenthesis to the enumeration. I don't need the parenthesis, so how do I do this in python? All I need is just to enumerate the list. this is what it does is

num =[(0, '1'), (1, '7'), (2, '11'), (3, '13')

this is my code

num =['1', '7', '11', '13']
print (list(enumerate(num,0)))

I need this below, but I don't the code.

num = [1,'1', 2,'7',3,'11',4,'13']

What is an enumeration in your definition if it is not what you posted? — Klaus D., Nov 15 '19 at 06:48
yes I don't need the Tuple but how do I change the code to print the new enumerated list without Tuple — Tom E. O'Neil, Nov 15 '19 at 06:49
Whats the use case , Do you want to print index, value without parenthesis ? — Vaibhav, Nov 15 '19 at 06:49
Edit your question to include the output you *want* the program to have. — kaya3, Nov 15 '19 at 06:49
Does this answer your question? [How do I convert a tuple of tuples to a one-dimensional list using list comprehension?](https://stackoverflow.com/questions/3204245/how-do-i-convert-a-tuple-of-tuples-to-a-one-dimensional-list-using-list-comprehe) — Ocaso Protal, Nov 15 '19 at 06:50
And BTW you need the parentheses, they are part of the syntax. But I suspect you want to do something you did not tell us about. — Klaus D., Nov 15 '19 at 06:50
Enumeration adds a count to each quoted number. like this [1,'1', 2,'7',3,'11',4,'13'] — Tom E. O'Neil, Nov 15 '19 at 06:51
Your code produces `[(0, '1'), (1, '7'), (2, '11'), (3, '13')]` cant relate to your output — Yugandhar Chaudhari, Nov 15 '19 at 06:54
I know Yugandhar Chaudhari but what code would prevent a tuple and just output an enumerated list with quotes. I can't seem to wrap my head around this. — Tom E. O'Neil, Nov 15 '19 at 06:56

Subhrajyoti Das · Accepted Answer · 2019-11-15T07:02:16.220

4

Simply run a loop as below:

num =['1', '7', '11', '13']
final_list = list()
for index, i in enumerate(num):
    final_list.extend((index, i))

print(final_list)
[0, '1', 1, '7', 2, '11', 3, '13']

edited Nov 15 '19 at 07:02

answered Nov 15 '19 at 06:59

Subhrajyoti Das

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Right on Subhrajyoti Das this answered the quetion. :) – Tom E. O'Neil Nov 15 '19 at 07:02

score 1 · Answer 2 · answered Nov 15 '19 at 07:05

1

Use itertools.chain.from_iterable:

from itertools import chain

num =['1', '7', '11', '13']
result = list(chain.from_iterable(enumerate(num)))
print(result)

Output:

[0, '1', 1, '7', 2, '11', 3, '13']

answered Nov 15 '19 at 07:05

Sayandip Dutta

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Yugandhar Chaudhari · Answer 3 · 2019-11-15T07:14:39.330

1

From you output you mean enumerate(num,1).

Just another short way.

We can add into a empty list after converting tuple to list. + here concats two lists

import functools
functools.reduce(lambda acc,x: acc + list(x),enumerate(num,1),[])

acc is [] is empty list initially and adding like ['hello'] + [1,2] = ['hello',1,2]

Output

[1, '1', 2, '7', 3, '11', 4, '13']

edited Nov 15 '19 at 07:14

answered Nov 15 '19 at 07:06

Yugandhar Chaudhari

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score 0 · Answer 4 · answered Nov 15 '19 at 07:18

0

It is similar to Yugandhar Chaudhari answer.

I use map(list, ...) to convert tuples to lists and then I can add all lists to empty list [] using sum() instead of + and reduce()

num = ['1', '7', '11', '13']

print(sum(map(list, enumerate(num, 1)), []))

answered Nov 15 '19 at 07:18

furas

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How do I enumerate a list without parenthesis?

4 Answers4