Python regular expression 'findall' is not returning all expressions

Asked Nov 18 '19 at 10:00

Active Nov 18 '19 at 10:01

Viewed 37 times

I want to find all expressions wrapped with "<" and ">" For example, in <2><1>, I want <2> and <1> seperately.

s = re.findall('<.*>', '<2><1>')

gives me only <2><1>, which is different from what I've intended. Can you give me an answer to find all of these expressions ? Thanks much in advance.

edited Nov 18 '19 at 10:01

asked Nov 18 '19 at 10:00

piljae.chae

insert input and output correctly in order to be able to help you – αԋɱҽԃ αмєяιcαη Nov 18 '19 at 10:01
4

You have a greediness issue. Change to `<.*?>` or `<[^>]*>`. – Amadan Nov 18 '19 at 10:01
2

[greedy regex expressions](https://stackoverflow.com/questions/2301285/what-do-lazy-and-greedy-mean-in-the-context-of-regular-expressions) – Sociopath Nov 18 '19 at 10:02
Thanks guys ! I've found the solution – piljae.chae Nov 18 '19 at 10:03
I have another question, I want to remove $$\$$50,000$$ this kind of expressions, and tried """ re.sub("$$\\$$.*?$$", "", text) """, which didn't work out quite well. Substituting \\ with \ didn't work as well. What is the problem ? – piljae.chae Nov 19 '19 at 00:52

Python regular expression 'findall' is not returning all expressions

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