Python3 dictionary compare, nested dictionaries with numpy arrays

Question

I want to compare dictionaries in python. I know that I can simply do a == b, if a and b are dictionaries. This also works for nested dictionaries, where a and b contain dictionaries themselves. However, it does not work if a and b contain numpy arrays of size>1:

import numpy as np
a = {"1": np.array([1, 2])}
b = {"1": np.array([1, 2])}
a == b

I get this error:

Traceback (most recent call last):
File "", line 1, in
ValueError: The truth value of an array with more than one element is ambiguous. Use a.any() or a.all()

I did check: this post and found the suggestion of import deepdiff from sumbudu which does what I want. However, is there an easier way using == and catching the error somehow?

Possible duplicate of [Comparing two dictionaries with numpy matrices as values](https://stackoverflow.com/questions/26420911/comparing-two-dictionaries-with-numpy-matrices-as-values) — Error - Syntactical Remorse, Nov 18 '19 at 14:16
Take a look at the very last answer for the duplicate above. — Error - Syntactical Remorse, Nov 18 '19 at 14:16

score 0 · Answer 1 · answered Nov 18 '19 at 20:37

Like this?

def equal_dictionaries(dic1, dic2):
    for key, value in dic1.items():
        key1 = key
        value1 = value
    for key, value in dic2.items():
        key2 = key
        value2 = value
    if np.array_equal(value1, value2) == False or key1 != key2:
        return False
    else:
        return True

Python3 dictionary compare, nested dictionaries with numpy arrays

1 Answers1