How to print a list using splat-operator (*) without spaces

Question

I'm trying to understand splat-operators in python. I have a code:

word = ['s', 't', 'a', 'c', 'k', 'o', 'v', 'e', 'r', 'f', 'l', 'o', 'w']
print(*word)

output:

s t a c k o v e r f l o w

I can't assign *word to some variable to check its type or smth else in debug. So I wounder which way print() gets the sequence of *word and if it's possible to print this word without spaces. Desirable output:

stackoverflow

@Carcigenicate I guess the question is confusing, how does he wants to understand the splat operator by using printting a list without spaces? — Dani Mesejo, Nov 19 '19 at 18:23
@DanielMesejo Because he doesn't understand `print` **_or_** splatting. It's an XY problem in this one imo — Maximilian Burszley, Nov 19 '19 at 18:23
Does this https://stackoverflow.com/questions/36901/what-does-double-star-asterisk-and-star-asterisk-do-for-parameters, answers your question? — Dani Mesejo, Nov 19 '19 at 18:24

Carcigenicate · Accepted Answer · 2019-11-19T18:30:09.660

6

You get that result because print automatically puts spaces between the passed arguments. You need to modify the sep parameter to prevent the separation spaces from being inserted:

print(*word, sep="")  # No implicit separation space
stackoverflow

edited Nov 19 '19 at 18:30

answered Nov 19 '19 at 18:20

Carcigenicate

43,494
9
68
117

That's exactly what I want. Does spat operator return some list again or what? – Pavel Antspovich Nov 19 '19 at 18:26
It simply unpacks the container. – Yash Nov 19 '19 at 18:26
5

@PavelAntspovich `print(*[1, 2, 3])` becomes `print(1, 2, 3)`. – Carcigenicate Nov 19 '19 at 18:27

score 1 · Answer 2 · answered Nov 19 '19 at 18:20

1

You can pass the separator you want, in your case:

print(*word, sep="")

or do:

print(''.join(word))

answered Nov 19 '19 at 18:20

Yash

3,438
2
17
33

How to print a list using splat-operator (*) without spaces

2 Answers2

Related