What happens when value is passed to operator overloader function in C++?

Question

I failed to understand the steps of compilation of this code. First, where is what is purpose of the default constructor, and why so many objects of type MyClass? link to sololearn where I saved the code

#include <iostream>
using namespace std;

class MyClass {
    public:
        int var;
        MyClass() { }
        MyClass(int a)
        : var(a) { }

        MyClass operator+(MyClass &obj) {
            MyClass res;
            res.var= this->var+obj.var;
            //'this' is refering to active (obj1)
            return res; 
        }
};

int main() {
    MyClass obj1(12), obj2(55);

    MyClass res = obj1+obj2;

    cout << res.var;
}
//I've not understood, its from a lesson

https://stackoverflow.com/questions/4421706/what-are-the-basic-rules-and-idioms-for-operator-overloading?rq=1 — 463035818_is_not_an_ai, Nov 20 '19 at 16:33
"*I've not understood*" What have you not understood? It's difficult to help someone if they don't explain what it is they don't know. — Nicol Bolas, Nov 20 '19 at 16:33

score 0 · Answer 1 · answered Nov 20 '19 at 16:55

If you suspect you don't need a piece of code, try compiling without it and you'll know pretty quickly whether your suspicion was correct or not.

When you remove the default constructor in the class you provided here's what happens:

..\Playground\: In member function 'MyClass MyClass::operator+(MyClass&)':
..\Playground\:11:21: error: no matching function for call to 'MyClass::MyClass()'
             MyClass res;
                     ^~~
..\Playground\:7:9: note: candidate: MyClass::MyClass(int)
         MyClass(int a)
         ^~~~~~~
..\Playground\:7:9: note:   candidate expects 1 argument, 0 provided
..\Playground\:4:7: note: candidate: constexpr MyClass::MyClass(const MyClass&)
 class MyClass {

Which is to say the problem is in the +operator implementation at the line MyClass res; . This line creates an instance of the object MyClassusing the default constructor, so there's no way the code snippet your provided works without a default constructor.

score 0 · Answer 2 · answered Nov 27 '19 at 07:50

0

The constructor without parameters is for the object that doesn't pass any value, the one that stores the sum of the two operand objects. ---simple---

answered Nov 27 '19 at 07:50

Hilary Diaz

39
1
6

What happens when value is passed to operator overloader function in C++?

2 Answers2