I try to write a program in Javascript that finds the biggest of three number using "if else" statements

Question

But there is a mistake and I can't find it. Plese help me!

let r=(gets());
let t=(gets());
let y=(gets());

let a=parseFloat(r);
let b=parseFloat(t);
let c=parseFloat(y);

if (a>==b && a>==c) { 
    print(a); 
} else if (b>==a && b>==c) {
    print(b); 
} else {
    print(c);
}

Convert to array and use `Array.max()` as described here https://stackoverflow.com/questions/1669190/find-the-min-max-element-of-an-array-in-javascript — ege, Nov 21 '19 at 10:39

Fiorila · Answer 1 · 2019-11-21T11:30:02.547

1

I think you are having a SyntaxError because in Javascript the comparison operators are these ones : https://developer.mozilla.org/en-US/docs/Web/JavaScript/Guide/Expressions_and_Operators#Comparison

So here is how you write your conditions:

if (a>=b && a>=c) { 
    console.log(a); 
} else if (b>=a && b>=c) {
    console.log(b); 
} else {
    console.log(c);
}

edited Nov 21 '19 at 11:30

answered Nov 21 '19 at 10:50

Fiorila

65
7

score 1 · Answer 2 · answered Nov 21 '19 at 10:54

You could take a nested approach and check only two values for each if statement.

if (a > b) {
    if (a > c) {
        console.log(a);
    } else {
        console.log(c);
    }
} else {
    if (b > c) {
        console.log(b);
    } else {
        consol.log(c);
    }
}

I try to write a program in Javascript that finds the biggest of three number using "if else" statements

2 Answers2