Rounding float using f-string

Question

Using %-formatting, I can round the number of decimal cases in a string:

pi = 3.14159265
print('pi = %0.2f' %pi)

And in output(in terminal) this would give me:

pi = 3.14

Can I use f-strings do this task? This feature has been added in Python 3.6

Does this answer your question? [Fixed digits after decimal with f-strings](https://stackoverflow.com/questions/45310254/fixed-digits-after-decimal-with-f-strings) — Florian Brucker, Jan 24 '22 at 09:35

ncica · Accepted Answer · 2019-11-21T12:52:56.183

6

Include the type specifier in your format expression

format specifier:

f'{value:{width}.{precision}}'

example:

# Formatted string literals
x = 3.14159265
print(f'pi = {x:.2f}')

edited Nov 21 '19 at 12:52

answered Nov 21 '19 at 12:48

ncica

1

in latest 3.8 you can even ```pi = 3.14159265; print(f'{pi =:.2f}') ``` – Sav Nov 21 '19 at 12:51

score 6 · Answer 2 · answered Nov 21 '19 at 12:52

6

>>> pi = 3.14159265
>>> print(f'{pi:.2f}')
3.14

answered Nov 21 '19 at 12:52

RGMyr

score 1 · Answer 3 · answered Apr 14 '21 at 18:37

Of course you can do this. The code section would be

pi = 3.14159265
print(f"{pi:.2f}")

Output: 3.14

if you want to print 3 decimal point then

pi = 3.14159265
print(f"{pi:.3f}")

Output: 3.142

You can also use .format method to do this job. like this:

pi = 3.14159265
print("{:.2f}".format(pi))

Output: 3.14

3 Answers3