How do i make an if statement referring to an aray?

Question

So as part of a program i need a line where if the input is not in a certain array the code wont carry on.

The best way to explain it is with a game of cards. You cant play a card that isnt in your hand(array) What would this look like in code form?

eg. if cardplayed (is not in) (myhand):
print("ect ect")

Get rid of the parentheses and also `is`. You also need to indent the `print` call — roganjosh, Nov 24 '19 at 12:28
Possible duplicate of [Finding the index of an item given a list containing it in Python](https://stackoverflow.com/questions/176918/finding-the-index-of-an-item-given-a-list-containing-it-in-python) — Lix, Nov 24 '19 at 12:28
@Lix but they're not trying to find the index, they just want to check membership — roganjosh, Nov 24 '19 at 12:29

score 2 · Answer 1 · answered Nov 24 '19 at 12:30

2

Simply use the not in operator:

if cardplayed not in myhand:
    print("etc etc")

The opposite would be

if cardplayed in myhand:
   print("I have this card, man")

answered Nov 24 '19 at 12:30

Laszlo Treszkai

seralouk · Answer 2 · 2019-11-24T12:31:55.663

1

Regardless of if myhand is a numpy array or not:

if cardplayed not in myhand:
    print("ect ect")

edited Nov 24 '19 at 12:31

answered Nov 24 '19 at 12:29

seralouk

1

I don't think you need to include the `numpy` package for this... It can be done in python itself... – Lix Nov 24 '19 at 12:30
the OP did not mention if it is a numpy or not. – seralouk Nov 24 '19 at 12:33
So how would i loop this until a card is picked that is acceptable? – C Plant Nov 24 '19 at 13:09

score 1 · Answer 3 · answered Nov 24 '19 at 12:32

Having a sequence, (a list in this example), one may check if an item is present within that sequence using the not in operator: https://docs.python.org/3.8/library/stdtypes.html#common-sequence-operations

hand = ['Card1', 'Card2', 'Card3']
card = 'Other card'
if card not in hand:
    print('Breaking...')

3 Answers3