list_name = "a"
list_element = "b"
I want to create a list in below format
a = ["b"]
How cani achieve this with format of list_name and list_element?
Thank you!
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Shalem
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Johnny Tam
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2its never a good idea to try and create variable names dynamically like that. you should consider revising your data structure and what you want to achieve – Chris Doyle Nov 25 '19 at 08:40
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`[list_element]`? – Sayse Nov 25 '19 at 08:42
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Use a dictionary instead: `lists = {}; lists[list_name] = list_element`. – Mark Tolonen Nov 25 '19 at 08:43
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bad idea but any way you can: `globals()[list_name] = [list_element]` – Brown Bear Nov 25 '19 at 08:43
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Possible duplicate of [How do I create a variable number of variables?](https://stackoverflow.com/questions/1373164/how-do-i-create-a-variable-number-of-variables) – SiHa Nov 25 '19 at 08:44
2 Answers
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You can do this easily using globals():
globals()[list_name] = [list_element]
out put:
In [1]: list_name = "a"
In [2]: list_element = "b"
In [3]: globals()[list_name] = [list_element]
In [4]: a
Out[4]: ['b']
Read more about globals().
Mehrdad Pedramfar
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1Can be done but should be discouraged, normally there is a better data structure to use. – Chris Doyle Nov 25 '19 at 09:25
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What you are trying to do here is to create variable names dynamically. Except if you really really need to do it, it is not recommended and can usually be avoided.
In Python, dictionaries can be used to solve this problem. A dictionary contains variables which can be called using "keys".
dict = {'a1' : "b1",
'a2' : "b2"}
The variable (here the string "b1") associated with the key 'a1' can be called using:
dict['a1']
Selven Ayasamy
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