I want to print the text slowly with the "cout" command but i dont really find any solution

Question

I would like to print a text slowly letter by letter like in this example

//example
int main()
{
    string message = "Lorem ipsum dolor sit amet, \nconsectetur adipisicing elit. Voluptatum, porro \nnesciunt laboriosam adipisci provident eum?\n";
    slow_print(message, 30);

    return 0;
}

but i want to have this effec twith the cout command but i dont find any solutions. If someone know how to fix this so please helpe me

write a loop that prints individual characters and add a sleep. — 463035818_is_not_an_ai, Nov 25 '19 at 19:20
Write a wrapper around `cout` that adds a delay between printing each character. Then use your new wrapper instead of `cout` directly. Straight forward. — Jesper Juhl, Nov 25 '19 at 19:20
You could print each character individually after a delay that you could specify with the ctime library. — Leo Guagenti, Nov 25 '19 at 19:20

score 3 · Answer 1 · answered Nov 25 '19 at 19:38

Ok, lets do this using cout. cout alone cannot do it, you need some io-manipulator or similar. I will use a type to indicate a string should be printed slowly:

struct slowly_printing_string { 
    std::string data; 
    long int delay; 
};

Next, we provide an output operator for this type:

std::ostream& operator<<(std::ostream& out, const slowly_printing_string& s) {
    for (const auto& c : s.data) {
        out << c << std::flush;        
        std::this_thread::sleep_for(std::chrono::milliseconds(s.delay));
    }
    return out;
}

It prints individual characters, flushes the stream (otherwise it could happen that you only see the full string at some later point), and waits for the specified time.

You can call it like this:

std::cout << slowly_printing_string{"hello world",1000};

Full Example

score 2 · Answer 2 · answered Nov 25 '19 at 19:43

I can do this by this code, but I don't recommend this code if you are developping to an enterprise:

#include <iostream>

#define LENGTH(x) (sizeof(x) / sizeof(x[0]))

using namespace std;

void printSlowCharacters(char * strToPrint) {
    while(*strToPrint) {
        cout << *strToPrint++ << endl;
        system("sleep 5");
    }
}


int main() {
    char * nome = "Davi";
    printSlowCharacters(nome);

    return 0;    
}

whiskeyo · Answer 3 · 2019-11-25T19:30:34.767

0

You can use #include <windows.h> and then in a loop you would print each character individually and intertwine it with Sleep(time_in_ms).

How is it possible? Each std::string is an array of characters, which is similar to char*, that way you can access each character by its index.

edited Nov 25 '19 at 19:30

answered Nov 25 '19 at 19:23

whiskeyo

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If you use [`std::this_thread::sleep_for`](https://en.cppreference.com/w/cpp/thread/sleep_for) you can generalize this advice beyond Visual C++ – user4581301 Nov 25 '19 at 19:26
an array of characters is not equal to `char*`. Arrays are not pointers! – 463035818_is_not_an_ai Nov 25 '19 at 19:28
Your solution assumes the Window's operating system. There are other operating systems out there: MicroCOs, Wind River, Linux, etc. – Thomas Matthews Nov 25 '19 at 20:31

I want to print the text slowly with the "cout" command but i dont really find any solution

3 Answers3