Given text with some phrases between /* */, I would like to remove the strings/phrases that are inside.
For example:
aaaabbbbb /*ppppqqqqrrrsss sstttuuu*/cccccddddeee
desired output:
aaaabbbbb /**/cccccddddeee
I tried to use re.sub(r'(\/*{2,3}[\s\n]*)(?:.*?[\s\n]*)*([\n\s]*\/*{2,3}) from python's REGEX, but the * symbol isn't recognized.
Does anyone know where I am going wrong?
(?<=\/\*)[\s\S]*?(?=\*\/)
This regex uses a positive lookbehind to assert the presence of a preceding /* and a positive lookahead to assert the presence of a trailing */, and between the two captures any characters across any number of lines.
As pointed out in the comments, * is a special regex character, and needs to be escaped with a backslash, like \*.
The python code is as follows:
import re
text = "aaaabbbbb /*ppppqqqqrrrsss\n\nss/tt*tu/uu*/cccccddddeee"
print(re.sub('(?<=\/\*)[\s\S]*?(?=\*\/)', '', text))
