How do I get user input to ONLY equal 1-8?

Question

I am trying to create a loop where the user is given choices 1-8 and if they do not choose 1-8, it loops them back around re-enter number 1-8. I am attempting to use a while loop with two conditions. What am I missing?

fm_select = int(input("Enter a number 1-8"))
while fm_select <= 8 and fm_select >= 1:

Which programming language is that? What does not work with the current code? — Nico Haase, Nov 29 '19 at 18:33

score 3 · Answer 1 · answered Nov 29 '19 at 18:38

Your ranges are wrong. You want the while loop to fail when they are correct, since you're trying to break out of the loop. So, you want your loop to check against every number that isn't between one and eight. Instead, do

fm_select = 0
while (fm_select < 1 or fm_select > 8):
    fm_select = int(input("Enter a number between one and eight: "))

"As long as their input is less than one or higher than eight, keep asking"

score 1 · Answer 2 · answered Nov 29 '19 at 18:39

1

something like this should work

while(True):
    fm_select = int(input("Enter a number 1-8"))
    if 0 < fm_select < 8:
        break
    print("try again")
 print("you have entered %d" %(fm_select) )

answered Nov 29 '19 at 18:39

ron

186
7

Thanks this makes sense. According to what I originally posted, is the syntax – Gordito Nov 29 '19 at 19:33

How do I get user input to ONLY equal 1-8?

2 Answers2