Python list comprehension count occurences

Asked Nov 30 '19 at 12:37

Active Nov 30 '19 at 12:37

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Suppose I have a list (or in this case a Series) that looks like this

[1,1,1,1,1,1,1,4,4,4,5,5,5,5,5,5,5,5,5,6,6,6,6,7,8,8,8,8,8]

I now want to convert this to a dict such that the key of the dict is the value of the list (here 1, 4, 5, 6, 7, 8) and that the value of the dict is the amount that the value of the list occures (here 7, 3, 9, 4, 1, 5).

I'd like to use a simple oneliner/list-comprehension but this topic is new to me for Python

asked Nov 30 '19 at 12:37

Wouter Vandenputte

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`import collections; counts = collections.Counter(your_list)` – Thierry Lathuille Nov 30 '19 at 12:39
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From ```collections import Counter``` and then ```d = Counter([1,1,1,1,1,1,1,4,4,4,5,5,5,5,5,5,5,5,5,6,6,6,6,7,8,8,8,8,8])```. – accdias Nov 30 '19 at 12:39
See also https://stackoverflow.com/questions/12282232/how-do-i-count-unique-values-inside-a-list – Thierry Lathuille Nov 30 '19 at 12:41

Python list comprehension count occurences

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