nodejs function with no body

Question

Could you please help me understand below code? I am not able mock method using sinon, what could be wrong with it?

const amqplib = require('amqplib');

async function getMessage() {
  const x = amqlib.connect({});
}

// Daemon process
getMessage();

module.exports = {
  getMessage,
};

mocking code as:

const mqConnMock = sinon.stub(amqplib, 'connect');

An async function returns a resolving promise when there is no method body. — ssc-hrep3, Dec 03 '19 at 14:47
To be precise ..I am having nodejs code looks like like below. const amqplib = require('amqplib'); async function getMessage() { const x = amqlib.connect({}); } // Daemon process getMessage(); module.exports = { getMessage, } mocking code as : const mqConnMock = sinon.stub(amqplib, 'connect'); Mock is not working this case. when i remove line 8 mocking works fine. Could you please help me fix this? — kishor kumar, Dec 03 '19 at 15:28
Does this help? https://stackoverflow.com/a/46227268/3233827 — ssc-hrep3, Dec 03 '19 at 20:56

score 0 · Answer 1 · answered Dec 03 '19 at 14:51

0

module.exports.getMessage = async function getMessage() {
  (...)
}

answered Dec 03 '19 at 14:51

David

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there is another declaration stating that it is a deamon process. I really didnt understand how it works – kishor kumar Dec 03 '19 at 14:58

nodejs function with no body

1 Answers1