Conditional in Mason code

Question

If I want to create a block of html code that displays if a boolean value in mason is true is there a way to do this without using print to print each line of the html code? i.e. is there a way to do something like this

<% if($boolean) { %>
<li>
<a href='http://somesite.com'>link</a>
</li>
<% } %>

instead of

<%perl>
if($boolean) {
print "<li>";
print "<a href='http://somesite.com'>link</a>";
print "</li>";
}
</%perl>

I found out the way to do this for anyone interested is by using % at the start of the line instead of surrounding the conditional start and end with <% %>. I'm posting answer in comments because I am a new user and need to wait 8 hours before answering my own question — thurmc, May 06 '11 at 21:56

clt60 · Accepted Answer · 2014-09-23T21:32:39.377

3

As you mention in your comment, you can:

% if($boolean) {
<li>
<a href='http://somesite.com'>link</a>
</li>
% }

edited Sep 23 '14 at 21:32

answered May 06 '11 at 22:43

clt60

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Conditional in Mason code

1 Answers1