RegEx: Capturing all individual instances of a repeating capture group

Question

I have a string that could be formatted in the following ways:

user-style-1
user-style-1-bold
user-style-1-italic
user-style-1-bold-italic

I'm attempting to capture (respectively):

nothing (does not match)
-bold
-italic
-bold and -italic (as separate captures)

This is my RegEx: ^user-style-\d+((-.+?)+?)$ (also potentially ^user-style-\d+(?:(-.+?)+?)$ since I don't care about the full capture, only the individual pieces of it). It captures:

nothing
-bold
-italic
-bold-italic and -italic

or (for the alternate)

nothing
-bold
-italic
-italic

I can't quite figure out how to get the repeating capture group to capture all individual instances rather than the entire thing and just the last instance or just the last instance.

Ah that does, in that it’s not possible to do what I want. Thanks! — Ben Black, Dec 05 '19 at 21:38

score 3 · Accepted Answer · answered Dec 05 '19 at 21:31

3

Take a look at something like this:

^user-style-\d+(-\w+)(-\w+)?$

Regex Demo

You will need a group per pattern that you want to capture. Refer to link posted by ggorlen and the accepted answer for that question for the reasoning.

answered Dec 05 '19 at 21:31

vs97

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3
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Just read that, unfortunately I was trying to have it be dynamic, guess I’ll need an alternate solution. – Ben Black Dec 05 '19 at 21:39
1

Just capture the tail after `user-style-\d+` and match a second time with that. – ggorlen Dec 05 '19 at 21:39
2

`[...s.matchAll(/^user-style-\d+(\-[\w-]+)$/gm)].map(e => e.pop().match(/-\w+/g))` – ggorlen Dec 05 '19 at 21:50
2

@ggorlen that's perfect, thanks! – Ben Black Dec 06 '19 at 00:33

score 0 · Answer 2 · answered Dec 05 '19 at 21:30

0

Try this RegEx: ^user-style-1(-bold)?(-italic)?$ it should capture all 4 cases

link: https://regex101.com/r/p8NbIv/1

answered Dec 05 '19 at 21:30

tgralex

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RegEx: Capturing all individual instances of a repeating capture group

2 Answers2