I want to call a C function from Fortran and receive a string of characters defined in the C function. I searched, but I couldn't find a working, straightforward answer, so far.
Actually I have found a workaround: receiving an array of characters instead, then using the intrinsic function transfer
to put the result into a Fortran string.
Here is my working code.
Fortran main program:
program pr
implicit none
character(200) :: stringa
call strfromc(stringa)
write (6,*) 'FPR stringa: "', trim(stringa),'"'
stop
end program pr
Fortran subroutine:
subroutine strfromc(stringa)
use iso_c_binding
implicit none
character(200) :: stringa
interface
subroutine getstrfromc(ld,d) bind(c,name='getString')
import :: c_int, c_ptr
integer(c_int) :: ld
type(c_ptr), value :: d
end subroutine getstrfromc
end interface
! declare a character array of type c_char and sufficient length:
character(c_char), dimension(200), target :: d1
integer :: ld1 ! will contain the string length
integer :: i
! the C pointer of character array d1 is passed:
call getstrfromc(ld1, c_loc(d1))
! read the first ld1 elements of array d1 as a character string, which will be returned:
stringa= transfer(d1(1:ld1), stringa)
write (6,*) 'SF d1: ', (d1(i),i=1,ld1)
write (6,*) 'SF stringa: "', trim(stringa),'"'
write (6,*) ''
return
end subroutine
C function:
#include <stdio.h>
#include <string.h>
void getString(int * lw, char * w) {
printf("Enter a string:\n");
scanf("%[^\n]", w); //scanning the whole string, including the white spaces
*lw= strlen(w);
printf("C: w: %s\n", w);
printf("C: lw: %d\n", *lw);
printf("\n");
return;
}
Can anyone suggest a more direct way?