Generating list of a random word, random number of times

Question

How do I generate a list that will contain only the type of monster randomly chosen in choice a random number of times (1-5)?

monsters = ("trolls", "ogres", "werewolves", "dragons")
choice = random.choice(monsters)

I have tried the following which delivers the number but how do I make a list out of it?

num = random.randint(1, 5)
print("Your hero must fight against: ", num, choice)

Welcome to Stack Overflow. What does "the type of monster randomly chosen in choice a random number of times (1-5)" mean? Can you provide an example or two? Please read [ask]. — ChrisGPT was on strike, Dec 10 '19 at 02:18
Possible duplicate of [Create list of single item repeated N times](https://stackoverflow.com/q/3459098/354577) — ChrisGPT was on strike, Dec 10 '19 at 02:29

score 0 · Answer 1 · answered Dec 10 '19 at 02:32

The following should work. It might be because you did not (correctly) import random


monsters = ("trolls", "ogres", "werewolves", "dragons")

choice = random.choice(monsters)
num = random.randint(1, 5)

print("Your hero must fight against: ", num, choice)

score 0 · Accepted Answer · answered Dec 10 '19 at 02:32

I am not sure whether I understand your questions, but I will answer it based on my understanding, please notify me if any mistakes.

Let's say you have a tuple of strings

monsters = ("trolls", "ogres", "werewolves", "dragons")

and you want to randomly pick random number of monsters from it, you can firstly generate a random number from the range by random.randint, and then use list generator to construct the list

nums = random.randint(1, 5) # nums = 2
monster_list = [random.choice(monsters) for i in range(nums)] 
# monster_list = ['ogres', 'trolls']

Generating list of a random word, random number of times

2 Answers2