Joining the 4 digits from the list each time

Question

I am trying to figure out how do I get the 4 digits each time when I loop back for the data given below

li = ['1','1','7','1','2','1','1','4','1','6','7','8','1','8','1','0','1','B','1','N','1','Y','1','T','1','O']

as the output:

Can Anyone help me out please?

Answer I suppose is like this

list=['1','2','3','4','5','6','5','4','7','8','9','1','0','6','4','3','4','5','4','7','8','9','0']
j=0
for i in len(list):
     if i%4==0:
         print("\n")
     print(list[i],end=' ')

Did you do any research? E.g. https://stackoverflow.com/q/434287/3001761 seems applicable. — jonrsharpe, Dec 12 '19 at 18:56
Where is your attempt? Simply dumping your assignment here is not acceptable. — Prune, Dec 12 '19 at 18:58

score 5 · Answer 1 · answered Dec 12 '19 at 18:57

5

You can use iter and zip:

list(map(''.join, zip(*[iter(li)]*4)))

answered Dec 12 '19 at 18:57

a_guest

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score 0 · Answer 2 · answered Dec 12 '19 at 19:02

This should work without priting the last 2 values as you show in your output. Using the step in the range:

li = ['1','1','7','1','2','1','1','4','1','6','7','8','1','8','1','0','1','B','1','N','1','Y','1','T','1','O']
for i in range(0,len(li),4):
    if len(''.join(li[i:i+4])) == 4:
        print(''.join(li[i:i+4]))#+str(li[i+1])+str(li[i+2])+str(li[i+3]))
    else:
        pass

Output:

Joining the 4 digits from the list each time

2 Answers2