AIX Find 2 lines below the search String

Question

I am trying to come up with a script or a command to find the line that is 2 lines below a search parameter in AIX. Please help with the correct command syntax.

Thanks in advance.

Perhaps this `awk ' /pattern/ { printf "%s", before2; } { before2= before1; before1= $0 "\n"; }` — Lorinczy Zsigmond, Dec 13 '19 at 17:23

Sandeep · Answer 1 · 2019-12-14T15:00:17.817

0

I have found the answer based on the answer given here: How to print 5 consecutive lines after a pattern in file using awk

awk '/pattern/ {print $0; {getline;getline; print}}' filename

edited Dec 14 '19 at 15:00

answered Dec 14 '19 at 14:46

Sandeep

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What will you get if the pattern occurs in three consecutive lines? – Lorinczy Zsigmond Dec 14 '19 at 18:55

AIX Find 2 lines below the search String

1 Answers1