Why am i getting this exception error ? ArrayOutOfBounds?

Question

I'm trying to check if the integers in an array are increasing. But I'm getting ArrayOutOfBounds exception, and I do not understand why. I'm new to programming.

for (int i =0; i > newArray.length ; i++){
    if (newArray[i] > newArray[i+1]){
        System.out.println("Not increasing");
    }
}

Thank you for your help.

The loop condition should be `i < newArray.length`, but actually the loop should not even be executing for a non zero sized array. — Tim Biegeleisen, Dec 16 '19 at 04:58
the stop condition shd be i < newArray.length. Additionally, newArray[i+1] is accessed, so in fact it shd be i < newArray.length-1. — Julian Chan, Dec 16 '19 at 04:59
@TimBiegeleisen yeah thanks i copied the wrong code from my IDE . — Akchene_ye, Dec 16 '19 at 05:07

score 0 · Answer 1 · answered Dec 16 '19 at 05:04

Let’s say your array length is 8 so the positions are from 0 to 7 In the last run of the for loop i=7 and i+1 =8 You don’t have newArray[i+1] You should put the first if inside a new if

if(i<(newArray.length - 1)){
if (newArray[i] > newArray[i+1]){
System.out.println("Not increasing");
}
}

score 0 · Accepted Answer · answered Dec 16 '19 at 05:04

0

the ArrayOutOfBounds exception happens when you are trying to access a non-existent position in the array.

The problem in your case is the newArray[i+1] which tries to access a position non-existent in your array. I recommend editing the condition i < newArray.length-1 : There are, of course, other ways to fix this but this is the easiest.

answered Dec 16 '19 at 05:04

N_Craft

70
7

i understand the exception but i did not think of this, thank you, it works now – Akchene_ye Dec 16 '19 at 05:11

Why am i getting this exception error ? ArrayOutOfBounds?

2 Answers2